Four cards, the aces of hearts, diamonds, spades and clubs are well shuffled, and then dealt two to player \(A\), the other two to player \(B\). \(A\) is then asked whether at least one of his two cards is red. He replies in the affirmative. In the light of this information we wish to calculate the probability that he holds both the red aces. Consider the argument: `We know that \(A\) has one red ace; without loss of generality we may suppose that it is the heart ace. Among the other three cards there is no reason why one more than another should be the diamond ace; one only out of three equally likely possibilities gives \(A\) both the red cards; the required chance is thus 1 in 3.' Criticize this argument, and produce a correct argument and answer.
It is given that $$f_n(x) = \sin x + \frac{1}{2}\sin 2x + \frac{1}{3}\sin 3x + \ldots + \left(\frac{1}{n}\right)\sin nx$$ For each integer \(n = 1, 2, 3, \ldots\) If \(x_0\) is any minimum of \(f_n(x)\) in the range \(0 < x < \pi\), prove that \(\sin x_0 < 0\), and hence that \(\sin x_0\) and \(\sin(n + \frac{1}{2})x_0 = \sin \frac{1}{2}x_0\). Deduce, by using mathematical induction on \(n\), that \(f_n(x)\) can never take negative or zero values in the range \(0 < x < \pi\), for any \(n \geq 1\).
In the complex polynomial equation $$z^n + a_{n-1}z^{n-1} + a_{n-2}z^{n-2} + \ldots + a_2z^2 + a_1z + 1 = 0,$$ it is given that the complex numbers \(a_{n-1}, a_{n-2}, \ldots, a_2, a_1\) satisfy $$|a_{n-1}| \leq 1, \quad |a_{n-2}| \leq 1, \quad \ldots, \quad |a_2| \leq 1, \quad |a_1| \leq 1.$$ Show that any root of the equation in the complex plane must lie in the annular region \(\frac{1}{2} < |z| < 2\).
A hill \(\frac{1}{2}\) mile high is in the shape of a spherical cap, with a horizontal circular rim, the radius of the sphere being 1 mile. A man walks up from a point of the rim to the peak at a steady speed of 3 miles per hour but never ascending at a gradient of more than \(\sin^{-1}(\frac{1}{3})\). Find the minimum time the walk can take him, and sketch roughly a possible minimum path (as seen from above); does it necessarily have no sharp corners?
\(p, n\) are positive integers with \(p\) a prime (\(\geq 2\)). Prove that the highest power of \(p\) that divides \(n!\) is exactly $$\left\lfloor\frac{n}{p}\right\rfloor + \left\lfloor\frac{n}{p^2}\right\rfloor + \left\lfloor\frac{n}{p^3}\right\rfloor + \ldots,$$ where \(\lfloor x \rfloor\) denotes the greatest integer not greater than \(x\). Find the highest power of 12 that divides \(120!\)
A particle is attached to the end of a light string which passes through a fixed ring. Initially the particle is moving in a horizontal circle, the string making an angle with the vertical. The string is then drawn upwards slowly through the ring until the distance of the particle from it has been halved. Assuming angular momentum is conserved, show that the string now makes an angle \(\alpha'\) with the vertical, where $$\frac{\sin^4 \alpha'}{\cos \alpha'} = 8 \frac{\sin^4 \alpha}{\cos \alpha}.$$
A circle of radius \(a\) lies inside a circle of radius \(2a\) and touches it. The two circles lie in the boundary of a uniform lamina which is free to rotate in a vertical plane about a fixed horizontal axis through a point \(P\) on the line of centres. Show that, as \(P\) is varied, the minimum period of oscillations of small amplitude is $$2\pi \left(\frac{a}{g}\right)^{\frac{1}{2}} \left(\frac{74}{9}\right)^{\frac{1}{2}}.$$
A light inextensible string \(AB\) of length \(l\) carries a small ring \(A\) at one end and a bob \(B\) at the other end. The ring can slide on a fixed horizontal wire, and initially the system hangs in equilibrium with \(AB\) vertical. At time \(t = 0\) a variable force begins to act on the ring, constraining it to move along the wire in such a way that its displacement is \(a \sin \omega t\). Find the components of acceleration of the bob along and perpendicular to \(AB\) and show that the angle \(\theta\) that \(AB\) makes with the downward vertical satisfies the differential equation $$\frac{d^2\theta}{dt^2} + \frac{g}{l}\sin \theta = \frac{a\omega^2}{l}\sin \omega t \cos \theta.$$ Assuming that \(\theta\) always remains small, calculate it as a function of time.
A particle \(A\) of mass \(m\) and a particle \(B\) of mass \(2m\) are connected by a light string of length \(a\) and slide on a smooth horizontal table. Initially both are at rest with the string taut, when another particle of mass \(m\) moving with velocity \(U\) perpendicular to \(AB\) embeds itself in \(A\). Show that \(A\) comes to rest again after a time \(\frac{2ma}{U}\). What is then the velocity of \(B\)?
The motion of a boomerang is illustrated by a particle of mass \(m\) moving in a horizontal plane with instantaneous speed \(v\) under the action of a tangential resistive force \(mkv^2 \cos \alpha\) and a normal force \(mkv^2 \sin \alpha\) tending to deflect the particle to the right, where \(\alpha\) is a constant acute angle. What is the shape of its path? If it is projected with speed \(v_1\), show that it returns to the point of projection after a time $$\frac{e^{2\pi \cot \alpha} - 1}{kU \cos \alpha}.$$