Simplify \(\dfrac{2x+5}{6x+7} - \dfrac{2x-1}{6x+5} - \dfrac{32x+33}{36(x+1)^2-1}\). and prove that, if \(a+b+c=0\), then \(a^3+b^3+c^3=3abc\).
Solve the equations:
Find a formula for the \(n\)th term of an A.P. whose first term is \(a\) and common difference \(d\), and determine the sum of the series \(1+3+5+7+\dots\) to \(n\) terms.