Problems

Filters
Clear Filters
1973 Paper 1 Q11
D: 1500.0 B: 1500.0

\(P\) is a variable point that moves so that the sum of its distances from fixed points \(S, S'\) is constant. By finding the equation of the locus of \(P\), or otherwise, show that the tangent to this locus at \(P\) bisects the angle \(SPS'\) externally.

1973 Paper 1 Q12
D: 1500.0 B: 1500.0

Let \(I_n(z) = \int_0^1 (1-y)^n(e^{yz}-1)dy\), for all \(n \geq 0\). Prove that for all \(n \geq 1\), \(I_{n-1}(z) = \frac{z}{n}I_n(z) + \frac{z}{n(n+1)}\). Deduce that for all \(n \geq 1\), \(e^z = \sum_{r=0}^n \frac{z^r}{r!} + \frac{z^n}{(n-1)!}I_{n-1}(z)\).

1973 Paper 1 Q13
D: 1500.0 B: 1500.0

The graph of \(y = f(x)\) for \(x \geq 0\) is a continuous smooth curve passing through the origin and lying in the first quadrant. It is such that, to each value of \(y\) there corresponds exactly one value of \(x\). Solving for \(x\), we obtain the equation \(x = g(y)\). Let \(F(X) = \int_0^X f(x)dx\), \(G(Y) = \int_0^Y g(y)dy\). Give a geometric argument to show that \(F(a) + G(b) \geq ab\) for any positive \(a, b\). When is equality obtained? Prove that \(u\log u - u + e^v - uv \geq 0\) if \(u \geq 1\) and \(v \geq 0\).

1973 Paper 1 Q14
D: 1500.0 B: 1500.0

Sketch the graph of the function \(f(x) = -x\textrm{cosec} x\) in the range \(0 < x < 2\pi\). Prove that there is a unique value \(\bar{x}\) of \(x\) which minimises \(f(x)\) in the range \(\pi < x < 2\pi\), and show that the corresponding minimum value of \(f\) is \(\sqrt{(1+\bar{x}^2)}\).

1973 Paper 1 Q15
D: 1500.0 B: 1500.0

Sketch the plane curve \(C\) whose polar equation is \(r = a\textrm{cosec}^2\frac{1}{2}\theta\), where \(0 < \theta < 2\pi\). Calculate: (i) the length of the arc \(C_1\) consisting of those points of \(C\) such that \(\frac{1}{2}\pi \leq \theta \leq \pi\); (ii) the area enclosed by the arc \(C_1\) and the radii \(\theta = \frac{1}{2}\pi\) and \(\theta = \pi\).

1973 Paper 1 Q16
D: 1500.0 B: 1500.0

(i) Find, for every real non-negative integer \(k\), all the solutions of the differential equation \[\left(\frac{dy}{dx}\right)^2 = x^{2k}\] that pass through the origin. (ii) Solve, for every real non-negative integer \(k\), the equation \[\frac{1}{y}\frac{dy}{dx} = x^{-1}(\log x)^k\] with the condition \(y = 1\) at \(x = e\).